股友提问要求:
KDJ 4日内出现2次金叉 macd 4日内出现一次金叉 然后再未来的4日内或者同时出现布林线喇叭口预警
布林线喇叭口的公式:
{BOLL}
BOLL:=MA(CLOSE,20);
UPPER:=BOLL+2*STD(CLOSE,20);
LOWER:=BOLL-2*STD(CLOSE,20);
BIASBOLL:=(UPPER-LOWER)/LOWER*100;
XG:=COUNT(BIASBOLL>REF(BIASBOLL,1),3)>0 AND COUNT(BIASBOLL0 AND C>UPPER;
XG=1;
kdj金叉:
KDJ低位金叉:=CROSS(KDJ.J,KDJ.K) AND MACD>REF(MACD,1) AND KDJ.D<20;
XG:COUNT(KDJ低位金叉,4)=2;
改成选股公式也可以 谢谢老师了!
171415.com解答:
BOLL:=MA(CLOSE,20);